From 43ae566766a8e2b8af4999825994db5ad850d5ce Mon Sep 17 00:00:00 2001 From: Justus Kuhlmann Date: Thu, 25 Jul 2024 14:58:13 +0200 Subject: [PATCH] better Notation on slide 11 --- talk.tex | 10 +++++----- 1 file changed, 5 insertions(+), 5 deletions(-) diff --git a/talk.tex b/talk.tex index 8f9d69b..773cb78 100644 --- a/talk.tex +++ b/talk.tex @@ -188,10 +188,11 @@ \framesubtitle{Construction} \begin{itemize} \item Example: construct a non-trivial observable, for which renormalisation drops out -$$\frac{A^R_{\pm}}{A^R_{ll}} = \frac{Z_{\rm A}}{Z_{\rm A}} \frac{(1+ b_{\rm A} (m_{q+} + m_{q-})/2}{(1+ b_{\rm A} m_{ql})} \frac{(1+\bar{b}_{\rm A}Tr[M_q])}{(1+ \bar{b}_{\rm A}Tr[M_q])} \frac{A_{\pm}}{A_{ll}}$$ - with $$(m_{q+} + m_{q-})/2=m_{ql}$$ + $$\frac{A_{\rm R}^{+-}}{A_{\rm R}^{ll}} = \frac{Z_{\rm A}}{Z_{\rm A}} \frac{(1+ b_{\rm A} (m_{{\rm q},+-}}{(1+ b_{\rm A} m_{{\rm q},ll})} \frac{(1+\bar{b}_{\rm A}Tr[M_{\rm q}])}{(1+ \bar{b}_{\rm A}Tr[M_{\rm q}])} \frac{A^{+-}}{A^{ll}}$$ + with $m_{{\rm q}, ij} = (m_{{\rm q}, i} + m_{{\rm q}, j})/2$ + \item fulfilled by $m_{{\rm q}, \pm}=m_{{\rm q}, l}\pm \Delta$ \item symmetric point \openlat~ensembles - \item unimproved vs improved chi vs improves sym + \item $\ca = 0$ vs $\ca(g_0^2)|_{\rm chi}$ vs $\ca(g_0^2)|_{\rm sym}$ \end{itemize} \end{frame} @@ -205,8 +206,7 @@ $$\frac{A^R_{\pm}}{A^R_{ll}} = \frac{Z_{\rm A}}{Z_{\rm A}} \frac{(1+ b_{\rm A} ( \begin{frame} \frametitle{Outlook} \begin{itemize} - \item finish $\zv$ via SF determination - \item $\bV$ through similar methods + \item finish $\zv$, $\bV$ and $\bar{b}_{\rm V}$ through SF \item further improvement and renormalisation currently in the works: \begin{itemize} \item vector and tensor current improvement ($c_{\rm V}$, $c_{\rm T}$)